3x的平方-6x=-33(x^2-2x+1)=03*(x-1)^2=0x=1
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3x的平方-6x=-3x^2-2x=-1x^2-2x+1=0(x-1)^2=0x=1
3x^2-6x=-33x^2-6x+3=0(x-1)(3x-3)=0x-1=0x1=13x-3=0x2=1
3x^2-6x=-33x^2-6x+3=03(x^2-2x+1)=03(x-1)^2=0x=1
