(-1)+(+2)+(-3)+(+4)+...+(-99)+(+100)怎么算

2025-12-17 09:17:10
推荐回答(3个)
回答1:

-1+2=1,100/2=50,(应为都是双数减单数,而一百内有50组这样的数),最后50*1=50

回答2:

1*2*3*4 = 24 = 25 - 1 = 5*5 - 1 = [(2*3) -1]^2 - 1 3*4*5*6 = 360 = 361 - 1 = 19*19 - 1 = [(4*5) -1]

回答3:

(-1)+(+2)+(-3)+(+4)+...+(-99)+(+100)=
(2+4+6...+100)-(1+3+5.....+99)=
50*(2+100)/2-50*(1+99)/2=25*(2+100-100)=50