如何分解因式x的4次方减1的4次方

如题谢了⊙.⊙~
2025-12-14 08:15:22
推荐回答(2个)
回答1:

x^4-1^4=(x²)²-(1²)²=(x²+1)(x²-1)=(x²+1)(x+1)(x-1)

回答2:

x4-1
=(x²+1)(x+1)(x-1)