在△ABC中,角C=30度,则cosAcosB-sinAsinB的值等于??

求详细的解答过程,,,!!!!THANK U
2025-12-16 19:59:31
推荐回答(2个)
回答1:

cosAcosB-sinAsinB=cos(A+B)=cos(180-C)=cosC=二分之根号三

回答2:

cos(A+B)=cosAcosB-sinAsinB
cosAcosB-sinAsinB=cos(A+B)=cos150=-根号3/2=-0.86602540378443864676372317075294