初二数学题

2025-12-15 09:14:25
推荐回答(1个)
回答1:

a²-1-2ab+b²
=(a²-2ab+b² )-1
=(a-b)^2-1
=(a-b+1)(a-b-1)

4ab-a²-4b²+1
=-(a²-4ab+4b²)+1
=1-(a-2b)^2
=(1+a-2b)(1-a+2b)

m²-4n²-4m+4
=m²-4m+4-4n²
=(m-2)^2-4n²
=(m-2+2n)(m-2-2n)

x²+2x-4y²-4y
=x²-4y²+2x-4y
=(x+2y)(x-2y)+2(x-2y)
=(x-2y)(x+2y+2)