急求解！！如何用C++编程：任意输入几个数字,再将它们的顺序颠倒，输出

用循环做就可以了呀.下面是代码看看行吧!
#include
void main()
{
int a,b; //a为输入内容,b为取余变量

cout<<"请输入一列数字!"< cin>>a;
cout<<"顺序颠倒后为:";
do //不断的除10取余,就可以了.
{
b=a%10;
cout< a=a/10;
}while(a!=0);
cout<}

#include
#include
using namespace std;

int main()
{
int i;
int total, num;
vector numArr;

cout << "Total: ";
cin >> total;
for (i = 0; i < total; ++i) {
cin >> num;
numArr.push_back(num);
}

for (i = total - 1; i >=0 ; --i) {
cout << numArr[i] << " ";
}

return 0;
}